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2 years ago

7

A quantity x varies directly with the square of y and inversely with z. If x=40 when y=4 and z=2, find x when y=10 and z=25. Do

not include "y=" in your answer.

1 answer:

olga2289 [7]2 years ago

5 0

Answer:

x=20

Step-by-step explanation:

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I need help on 28! Write your answer as a power please :)

Tanya [424]

it is probably 11,514

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3 years ago

how would a enter a payment that was accepted with a 4 month, 8% note in a payment of a $4800.00 account

Anon25 [30]

Answer:

Enter a payment of 5192.52.

Step-by-step explanation:

Consider the provided information.

The payment is $4800 with a 4 month, 8% note.

The amount can be calculated as:

$Amount=p(1+\frac{r}{m})^{mt}$

Where <em>p</em> is money invested, <em>r</em> is annual interest rate, <em>t</em> is number of years and <em>m</em> is number of period.

Now substitute p = 4800 r = 0.08 and m = 4 in the above formula.

$Amount=4800(1+\frac{0.08}{4})^4$

$Amount=4800(1+0.02)^4$

$Amount=4800(1.02)^4$

$Amount=4800(1.08243216)$

$Amount=5195.52\ approximately$

Hence, enter a payment of 5192.52.

6 0

3 years ago

370 is 125% of what number?

bonufazy [111]

Answer:

125/100 x N = 370

x 100 x 100

125n = 37,000 (since your multiplying what you got to the variable)

Divide by 125

N = 296

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2 years ago

When John bought his new computer he purchased an online computer help service. The help service has a yearly fee of 25.50 and a

Tems11 [23]

First you need to find out how much he spends each session which would be___?

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3 years ago

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

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2 years ago