Answer:
- Exact distance =
feet - Approximate distance = 127.2792 feet.
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Explanation:
The area of the square is 8100 square feet, abbreviated ft^2.
Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.
If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).
Use the pythagorean theorem to find the hypotenuse.

The distance from 1st to 3rd base is roughly 127.2792 feet.
Answer:
x = 1/3 ln(2)
Step-by-step explanation:
e^(3x)+6=8
Subtract 6 from each side
e^(3x)+6-6=8-6
e^(3x) = 2
Take the natural log of each side
ln (e ^3x) = ln (2)
3x = ln(2)
Divide by 3
3x/3 = 1/3 ln(2)
x = 1/3 ln(2)
Discriminant D is given by:
D=b²-4ac
Implication of discriminant is as follows:
D<0 two zeros that are complex conjugate
D=0 one real zero of multiplicity 2
D>0 two distinct real zers
D= (+ve perfet square) two distinct rational zeros
From:
12x^2+10x+5=0
plugging in the equation we get:
10²-4×12×5
=100-240
=-140
thus
D<0
Answer is:
<span>A two irrational solutions </span>