X57 I think no just doing this for points so made a random number lol
Answer: The length of the rectangle is 37.5 inches and the width is 12.5 inches
Step-by-step explanation: The dimensions of the rectangle is not given but we have clues given. The length is given as three times it’s width which means if the width is W, then the length would be given as 3W (three times the width). Also the perimeter is given as 100 inches and the formula for the perimeter is;
Perimeter = 2(L + W)
We can now insert the known values as follows;
100 = 2(3W + W)
100 = 2(4W)
100 = 8W
Divide both sides of the equation by 8
12.5 = W
Having calculated the width as 12.5 inches, the length now becomes
L = 3W
L = 3 x 12.5
L = 37.5
Hence the length is 37.5 inches and the width is 12.5 inches
Answer:
38.72%
Step-by-step explanation:
Estimated attendance = 1,000
The actual value of attendance = 1,632
We need to find the percent error of Shaun's estimate. Using the formula as follows :
Put all the values,
So, the percent error of Shaun's estimate is 38.72%.
The perimeter is 38.4 inches
Answer:
Step-by-step explanation:
The distance formula states that the distance between two points 
and 
is 
.
The two points we have are 
and 
. Plugging these numbers into the distance formula, we have
.
Simplifying with order of operations, first using the distributive property, gives
.
Squaring and adding gives
which is the answer in simplest form. This also rounds to about 12.04.
