Answer:
The most appropriate value of the critical value is 2.289.
Step-by-step explanation:
We are given that a researcher takes a random sample of 41 bulbs and determines that the mean consumption is 1.3 watts per hour with a standard deviation of 0.7.
We have to find that when constructing a 97% confidence interval, which would be the most appropriate value of the critical value.
Firstly, as we know that the test statistics that would be used here is t-test statistics because we don't know about the population standard deviation.
So, for finding the critical value we will look for t table at (41 - 1 = 40) degrees of freedom at the level of significance will be
.
Now, as we can see that in the t table the critical values for P = 1.5% are not given, so we will interpolate between P = 2.5% and P = 1%, i.e;

So, the critical value at a 1.5% significance level is 2.289.
Answer:
35
Step-by-step explanation:
I hope this helps you.
12+24=38
38÷6=31
31+4=35
Answer:
43.68
Step-by-step explanation:
43x+2=64+455−766
Step 1: Simplify both sides of the equation.
43x+2=64+455−766
43x+2=64+455+−766
43x+2=(64+455+−766)(Combine Like Terms)
43x+2=−247
43x+2=−247
Step 2: Subtract 2 from both sides.
43x+2−2=−247−2
43x=−249
Step 3: Divide both sides by 43.
43x
/43 = −249
/43
x = −249
/43
Answer:
x = −249
/43
Ratio is 10:16, so to win 50, its 50:190, so you need to play 190 games to win 50