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nadezda [96]
2 years ago
12

Solve for x -2x + 2 = x -13

Mathematics
2 answers:
Tanya [424]2 years ago
7 0

Isolate with the variable by dividing each side by factors that don't contain the variable. So, x= 15

yan [13]2 years ago
6 0

Answer:

x = 5

Step-by-step explanation:

Add 2x to both sides: 2 = 3x - 13

Add 13 to each side: 15 = 3x

Divide both sides by 3: 5 = x

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Can someone answer this question please (picture)
erik [133]

Answer:

31.5 units^2

Step-by-step explanation:

Rectangle area (RA) = l × w

Triangle area (TA) = (bh)/2

RA = 3 × 7

RA = 21

TA = (7 × 3)/2

TA = 21/2

TA = 10.5

(Triangles are congruent as shown by the lines on each side of the triangle so I can calculate area of both of them together as I just did)

Add areas together

21 + 10.5 = 31.5

7 0
3 years ago
Eugene went to the ice cream shop after school. The large dish of ice-
KIM [24]

Answer:

the answer would be 4

Step-by-step explanation:

10  -  4 =  6 divided by 1.25 = 4

hope this helps!

8 0
3 years ago
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Find the slope of the line passing through the points (-9, -6) and (-4, 5)
Masja [62]

Answer:

11/5 slope

Step-by-step explanation:

5-(-6) -4-(-9)

11/ 5

4 0
3 years ago
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5t=24.5 what does t represent
Inessa [10]
Divide both sides by 5 to get t by itself, then you have your answer
4 0
3 years ago
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Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=​
Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

8 0
3 years ago
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