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ira [324]
2 years ago
6

Help me please!! I need all answered

Mathematics
1 answer:
erastovalidia [21]2 years ago
3 0
Domain-(-♾,♾),{x|xE(all real number sign (R))
Range-[-7,-3],{y|-7 ≤y ≤-3}
Period-2π/3
Amplitude-2
Transformation-Compare the equation to the parent function and check to see if there is a horizontal or vertical shift
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What is 1/8 of 16 pls I really need to get this done
KatRina [158]

Answer:

2

Step-by-step explanation:

We take the denominator.

That is 8.

8 goes in twice.

16÷8=2

3 0
3 years ago
Read 2 more answers
What is the slope of the line?​
damaskus [11]

Answer:

- 7/4

Step-by-step explanation:

1) (y2 - y1)/(x2 - x1)

2) pick two points, mine were (1,-3) and (-3,4)

3) Substitute the values (4+3)/(-3-1)

4) Solve and no matter what points you’ll get -7/4

3 0
3 years ago
Find the missing terms in the<br>sequence 27, ? , 23, ? , 19,...<br>good luck​
Vikki [24]
Is it subtract by 2? So I think it would be 27,25,23,21, 19
8 0
3 years ago
Solving Exponential Equations (lacking a common base)<br> 31^d=38
Bond [772]

Answer:

d = log 38/log31

d = 1.06

Step-by-step explanation:

31 ^ d = 38

Take log of both sides since the exponential equation have different base (always)

d log 31 = log 38

d = log 38 / log 31

d = 1.58 / 1.491

d = 1.06.

We can actually check to see if this is correct.

Substituting d = 1.06

31^ 1.06 = 38.092

(You see, that's approximately correct)

Keep learning, maths is fun!

8 0
3 years ago
A jet’s speed in still air is 240 mph. One day it flew 700 miles with a tailwind (the wind pushing it along) and then returned t
Bess [88]

Speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

As given in the question,

Given data:

Jet speed in still air = 240mph

Let x be the speed of the wind.

Speed with tail wind = 240 +x

Distance covered with tail wind = 700miles

Time taken by jet with tail wind

= Distance/ speed

= 700 / (240 +x)  __(1)

Speed against the wind = 240 - x

Distance covered against the wind = 700miles

Time taken by jet against the wind

= Distance/ speed

= 700 / (240 - x)  __(2)

Total time taken is 6 hours

[700 / (240 +x)] + [700 / (240 - x)] = 6

⇒ 700( 240 -x + 240 + x) = 6 (240 +x)(240 - x)

⇒ 700 ( 480) = 6 ( 240² -x²)

⇒ 700 (80) = 57600 -x²

⇒ x² = 57600 - 56000

⇒ x² = 1600

⇒ x = √1600

⇒ x= 40 mph

Therefore, speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

Learn more about speed here

brainly.com/question/28224010

#SPJ1

6 0
10 months ago
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