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ira [324]
2 years ago
6

Help me please!! I need all answered

Mathematics
1 answer:
erastovalidia [21]2 years ago
3 0
Domain-(-♾,♾),{x|xE(all real number sign (R))
Range-[-7,-3],{y|-7 ≤y ≤-3}
Period-2π/3
Amplitude-2
Transformation-Compare the equation to the parent function and check to see if there is a horizontal or vertical shift
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On his last birthday, Arnie was 144 centimeters tall. Since that time, he has grown h centimeters. Which expression tells Arnie'
telo118 [61]

Answer:

H(M) = (1)M + 10

Step-by-step explanation:

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Factor: 3x^(2)-16x+16
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Answer:

3 {x}^{2}  - 16x + 16 \\ 3 {x}^{2}  - 12x - 4x + 16 \\ 3x(x - 4) - 4(x - 4) \\ (3x - 4)(x - 4)

Step-by-step explanation:

I hope it helped U

stay safe stay happy

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2 years ago
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Write the faction ration for each of the following.<br> If m
Aleksandr-060686 [28]

Answer:

\tan D=\frac{7}{4},\\\\\sin D=\frac{7}{8.1}, \\\\\cos D=\frac{4}{8.1}, \\\\GI=5.0

Step-by-step explanation:

In any right triangle, the following is true:

The sine of any angle is equal to its opposite side divided by the hypotenuse of the triangle. (o/h)

The cosines of any angle is equal to its adjacent side divided by the hypotenuse. (a/h)

The tangent of any angle is equal to its opposite side divided by its adjacent side. (o/a)

Thus,

\text{3. }\\\tan D=\frac{7}{4},\\\\\sin D=\frac{7}{8.1}, \\\\\cos D=\frac{4}{8.1},

\text{4. }\tan 68^{\circ}=\frac{GI}{2},\\GI=2\tan68^{\circ}=4.95017370683\approx \boxed{5.0}

4 0
3 years ago
QUESTION 11.1
lawyer [7]

The group paid $ 5250 at first city and $ 6250 at second city

<u>Solution:</u>

Let x = the charge in 1st city before taxes

Let y = the charge in 2nd city before taxes

The hotel charge before tax in the  second city was $1000 higher than in the first

Then the charge at the second hotel before tax will be x + 1000

y = x + 1000 ----- eqn 1

The tax in the first city was 8.5% and the  tax in the second city was 5.5%

The total hotel tax paid for the two cities was $790

<em><u>Therefore, a equation is framed as:</u></em>

8.5 % of x + 5.5 % of y = 790

\frac{8.5}{100} \times x + \frac{5.5}{100} \times y = 790

0.085x + 0.055y = 790 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Substitute eqn 1 in eqn 2</u></em>

0.085x + 0.055(x + 1000) = 790

0.085x + 0.055x + 55 = 790

0.14x = 790 - 55

0.14x = 735

<h3>x = 5250</h3>

<em><u>Substitute x = 5250 in eqn 1</u></em>

y = 5250 + 1000

<h3>y = 6250</h3>

Thus the group paid $ 5250 at first city and $ 6250 at second city

8 0
3 years ago
What is the sum of the polynomials?
Olenka [21]
(7x3 – 4x2) + (2x3 – 4x2) = 9x3 – 8x2

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