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abruzzese [7]
3 years ago
12

In a football game, one team makes 5 plays. The result of those plays are: gain of 7 yards, gain of 2 yards, loss of 5 yards, lo

ss of 23 yards, gain of 16 yards. What is the overall gain or loss of all 5 plays?
Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer: Loss of 3 yards

Step-by-step explanation:

The overall gain or loss of all 5 plays will be gotten by adding all the results of the plays given and this will be:

= 7 + 2 - 5 - 23 + 16

Collect like terms

= 7+2+16-5-23

= 25 - 28

= -3

The overall loss of all 5 plays will be -3 yards or loss of 3 yards

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MArishka [77]

Answer:

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7 0
3 years ago
Place ( ) symbols in this problem to make a true statement: 4 + 5 × 2 = 18​
yanalaym [24]

<em>Answer:</em>

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(4+5)*2

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5 0
3 years ago
Read 2 more answers
A detergent company periodically tests its products for variations in the fill weight. To do this, the company uses x-bar and R
maw [93]

Answer:

10.9361

Step-by-step explanation:

The lower control limit for xbar chart is

xdoublebar-A2(Rbar)

We are given that A2=0.308.

xdoublebar=sumxbar/k

Rbar=sumR/k

xbar      R

5.8        0.42

6.1         0.38

16.02    0.08

15.95    0.15

16.12     0.42

6.18      0.23

5.87     0.36

16.2      0.4

Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8

Xdoublebar=88.24/8

Xdoublebar=11.03

Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8

Rbar=2.44/8

Rbar=0.305

The lower control limit for the x-bar chart is

LCL=xdoublebar-A2(Rbar)

LCL=11.03-0.308*0.305

LCL=11.03-0.0939

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8 0
3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
3 years ago
1/3 of students at a school are boys. If there are 600 students at the school, how many are girls?
Temka [501]

Answer:

200 students are boys and rest of 400 are girls

Step-by-step explanation:

Given that:

Total students = 300

1/3 students of total are boys

so.

Boys = 1/3(600)

Boys = 200

For finding number of girls:

Girls = total - boys

Girls = 600 - 200

Girls = 400

i hope it will help you!

8 0
4 years ago
Read 2 more answers
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