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2 years ago

Can you find the perimeter and area of the figure?

Mathematics

2 answers:

s344n2d4d5 [400]2 years ago

7 0

Answer:

perimeter of triangle=48 units.

area of triangle=96cm²

stellarik [79]2 years ago

3 0

Answer:

perimeter = 46

Area = 96 units^2

Step-by-step explanation:

The given is a right triangle and in right triangle the square length of hypotenuse is equal to sum of other two sides's square length

12^2 + 16^2 = hypotenuse^2

144 + 256 = hypotenuse^2

400 = hypotenuse^2

20 = hypotenuse

The perimeter is equal to the sum of all side lengths

12 + 16 + 18 = 46

The area of a triangle is calculated by multiplying height to the base and that divided by two

16 × 12 ÷ 2 = 96 units^2

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Answer:

The expression of the ellipse is: $\frac{x^2}{4} + y^2 = 1$

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The area of the triangle is $2\sqrt{3}$ = 3.4641 square feet.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse will be equal to the sum of the squares of the other two sides.

In the given triangle, the hypotenuse is the side that is represented by c. The other sides on the triangle are represented by the values a and b.

Step 2:

Assume the other side of the triangle measures x units.

So according to the Pythagorean theorem,

$4^{2} = (2\sqrt{3} )^{2} + x^{2} , x^{2} = 4^{2} - (2\sqrt{3} )^{2} .$

$x^{2} = 16 - 12 =4, x =2.$

So the other side of the triangle, b measures 2 feet.

Step 3:

The area of a triangle is half the product of its base length and height.

The base length of this triangle is $2\sqrt{3}$ feet and the height is 2 feet.

The area of the triangle $= \frac{1}{2} (2\sqrt{3} )(2) = 2\sqrt{3} = 3.4641.$

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