1. 868 ÷ 4 = 217
2. 657 ÷ 2 = 328.5
3. 8,473 ÷ 7 = 1,210.428
Hope it helps!
Answer:they would meet at 1 pm
Step-by-step explanation:
The distance between Quebec City and New York City is 520 miles.
At the point where Kate and Will meet, they would have travelled 520 miles.
Let t represent the time it takes Kate to travel a certain distance before they met.
Distance = speed × time
If Kate drives at 55mph, the distance covered would be
55 × t = 55t.will drives at 75 mph
Since Will left same that that Kate left, distance travelled by Will in t hours would be
75 × t = 75t
Since the total distance covered is 520 miles, it means that
55t +75t = 520
130t = 520
t = 520/130 = 4
9 am + 4 hours = 1 pm
The answer is -32. This is because when you multiply to negatives it becomes a positive. So its 8*-4 making the answer be -32.
Answer: -1.409, -1.48, 0.007 , 0.10, 0.17
Hope this helps
