X + 3/4 > 11/4
X > 8/4
X > 2
So make a rectangle that extends from 2 and above
In inequalities normal athematic are used the only difference is that you flip the operator when dividing over -1 or taking inverse
Answer:
Step-by-step explanation:
4u + 8v = -3u + 2v
Solving 4u + 8v = -3u + 2v
Solving for variable 'u'.
Move all terms containing u to the left, all other terms to the right.
Add '3u' to each side of the equation. 4u + 3u + 8v = -3u + 3u + 2v
Combine like terms: 4u + 3u = 7u 7u + 8v = -3u + 3u + 2v
Combine like terms: -3u + 3u = 0 7u + 8v = 0 + 2v 7u + 8v = 2v
Add '-8v' to each side of the equation. 7u + 8v + -8v = 2v + -8v
Combine like terms: 8v + -8v = 0 7u + 0 = 2v + -8v 7u = 2v + -8v
Combine like terms: 2v + -8v = -6v 7u = -6v
Divide each side by '7'. u = -0.8571428571v
Simplifying u = -0.8571428571v
1) 9m
2) 1/64
3) 50d^3
4) pq^2 (p-q) (p-q)
= pq^2 ( p^2 - 9p -9p +18)
= pq^4 - 18p^2q^2 + 8pq^2
= q^2 - 18p + 8
Step-by-step explanation:
90 - 60 = 30
30 - 18 = 12
X=12
