<span>With the mean of 40k and standard deviation of 5k, we need to find P(x>=30k). P((30k-40k)/5k) = P(z<-2) = 1-0.0228 which is equal to 0.9772. There is a 97.72% chances that the starting salary will be at least 30k.</span>
Answer:
Step-by-step explanation:
-38,827
if the sequence goes on without any changes
it will be d+8a
Answer: x = 9
Explanation:
Answer:
9 times 4 divide by 6
Step-by-step explanation:
it might be it
