Isocoleese means that 2 sides and hence 2 angles are same measure
acute means that all 3 angles are less than 90 degrees
We can rule out choice I since acut means less than 90
II is a possibility, but it doesn't best describe it
III. that is true, but it doesn't include the isocileese part
IV. that is true, but doesn't include the acute part
not sure, either III or IV
Answer:
Simplifying 9m + -3 + -7m = 0
Reorder the terms: -3 + 9m + -7m = 0
Combine like terms: 9m + -7m = 2m -3 + 2m = 0 Solving -3 + 2m = 0
Solving for variable 'm'. Move all terms containing m to the left, all other terms to the right.
Add '3' to each side of the equation. -3 + 3 + 2m = 0 + 3 Combine like terms: -3 + 3 = 0 0 + 2m = 0 + 3 2m = 0 + 3 Combine like terms: 0 + 3 = 3 2m = 3
Divide each side by '2'. m = 1.5
Step-by-step explanation:
Hope this helps :)
L = total length
D = number of days
they add 3 miles per day which = 3D
equation: L = 59 +3D
if they worked for 34 days, replace D with 34 to get:
L = 59 +3(34) =
L=59 + 102
L=161 miles total length after 34 days
Answer:
A. b(w) = 80w +30
B. input: weeks; output: flowers that bloomed
C. 2830
Step-by-step explanation:
<h3>Part A:</h3>
For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...
b(w) = f(s(w)) = 2(40w) +30
b(w) = 80w +30 . . . . . . blooms over w weeks
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<h3>Part B:</h3>
The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.
The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.
Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).
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<h3>Part C:</h3>
For 35 weeks, the number of flowers that bloomed is ...
b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks
Speed (v) = distance (d) / time (t)
so either the second or third. if this is realistic deer can't run 100 miles per hour so is say the second initially but to check what is .25miles/25s convert to hours. (3600 seconds in an hour) so .25*3600=900 then 900miles/25hour= 36miles/ hour.
