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nataly862011 [7]
3 years ago
14

N^2-n/3=7 complete the square

Mathematics
1 answer:
monitta3 years ago
5 0

Answer:

You need to add 1/36th to both sides of the equation, giving you the expression

n^2 - \frac{1}{3}n + \frac{1}{36} = 7\frac{1}{36}\\

Which can be expressed as:

(n - \frac{1}{6})^2 = 7\frac{1}{36}

Step-by-step explanation:

We need to add a term that is the the square of half the coefficient of the second term.

n^2 - n/3 = 7\\n^2 - \frac{1}{3}n = 7\\n^2 - \frac{1}{3}n + \frac{1}{36} = 7\frac{1}{36}\\(n - \frac{1}{6})^2 = 7\frac{1}{36}

Let's check the answer by expanding:

(n - \frac{1}{6})^2 = 7\frac{1}{36}\\n^2 - \frac{1}{6}n - \frac{1}{6}n + \frac{1}{36} = 7\frac{1}{36}\\n^2 - \frac{1}{3}n + \frac{1}{36} = 7\frac{1}{36}\\n^2 - \frac{1}{3}n = 7

Which verifies the answer.

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