If 5x + 2 = 17, then 10x + 4 = 34 True False selle Corporation. All Rights Reserved
1 answer:
You might be interested in
Answer:
Andrew walks more steps than Sarah.
Step-by-step explanation:
The question is incomplete. The complete question is :
Andrew and Sarah are tracking the number of steps they walk. Andrew records that he can walk 6000 steps in 50 minutes. Sarah writes the equation y=118x, where y is the number of steps and x is the number of minutes she walks, to describe her step rate. This week, Andrew and Sarah each walk for a total of 5 hours. Who walks more steps?
Solution:
Given:
Andrew walks 6000 steps in 50 minutes.
Number of steps Sarah walks is given by the equation :
where is the number of steps and
is the number of minutes she walks.
Finding the number of steps each walks in 5 hours.
Total number of minutes in 5 hours =
For Andrew:
Using unitary method:
If in 50 minutes Andrew walks = 6000 steps.
In 1 minute he will walk = = 120 steps
In 300 minutes he will walk = steps
Thus, Andrew will walk 36,000 steps in 5 hours.
For Sarah:
We will plugin in the equation and solve for
.
We have:
∴
Thus, Sarah will walk 35,400 steps in 5 hours.
Therefore, Andrew walks more steps than Sarah as .
The given sequence is
a₁, a₂, ...,
Because the given sequence is an arithmetic progression (AP), the equation satisfied is
where
d = the common difference.
The common difference may be determined as
d = a₂ - a₁
The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..
The sum of the first n terms is
Example:
For the arithmetic sequence
1,3,5, ...,
the common difference is d= 3 - 1 = 2.
The n-th term is
For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
Th sum of th first 10 terms is
S₁₀ = (10/2)*(1 + 19) = 100
a₁, a₂, ...,
Because the given sequence is an arithmetic progression (AP), the equation satisfied is
where
d = the common difference.
The common difference may be determined as
d = a₂ - a₁
The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..
The sum of the first n terms is
Example:
For the arithmetic sequence
1,3,5, ...,
the common difference is d= 3 - 1 = 2.
The n-th term is
For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
Th sum of th first 10 terms is
S₁₀ = (10/2)*(1 + 19) = 100