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jolli1 [7]
3 years ago
15

HELP I NEED HELP ASAP

Mathematics
2 answers:
AlexFokin [52]3 years ago
8 0
The answer is D your welcome
Julli [10]3 years ago
5 0

Answer:

No spam no help

Step-by-step explanation:

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What would go in the blank?
luda_lava [24]

Answer:44

Step-by-step explanation:

Because all angles are the same on a triangle

8 0
3 years ago
Read 2 more answers
Given that P = (-5, 11) and Q = (-6, 4), find the component form and magnitude of vector QP.
neonofarm [45]
Vector QP= (-5+6, 11-4) = (1, 7)
its magnitude is QP= sqrt( 1 + 49)= sqrt (50)=5sqrt2
7 0
3 years ago
Raymond was riding a zip-cable from the top of a viewing post. The cable is 70 yards long. The viewing post is 56 yards high and
Marysya12 [62]

Answer:

C. 42 yards

Step-by-step explanation:

You may recognize this as a 3-4-5 right triangle with a scale factor of 14. The two given sides are 5·14 = 70 and 4·14 = 56. Then the missing side is 3·14 = 42.

If not, you can use the Pythagorean theorem in the usual way:

... hypotenuse² = leg1² +leg2²

... 70² = 56² +leg2²

... leg2 = √(70² -56²) = √1764 = 42 . . . . yards

The cable is anchored 42 yards from the  base of the tower.

8 0
3 years ago
Check all that apply. I need help pls
Maru [420]
A,D,E that’s the awnser I came up with
8 0
3 years ago
20 POINTS
USPshnik [31]

Answer:

a) Only the first one is an identity.

Step-by-step explanation:

1). 8 cos O tan O csc O = 8   simplifies to:

cos O tan O csc O = 1

cos O * (sin O / cos O) * (1 /sin O)

=  cos O sin O / cos O sin O

= 1

So it is identity.

2) 13 sec^2 O/ cos^2 O - tan^2 O / cos^2O

= 13 sec^2 O - tan^2 O / cos^2 O

Now  sec^2 O = 1 + tan^2 O, so we have:

(13( 1 + tan^2 O) - tan^2 O) / cos^2 O

= (12 tan^2 O + 13) / cos^2 O

This is not always = 2 so its not an identity.

4 0
3 years ago
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