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3 years ago

Lololol helpppo plssss

Mathematics

2 answers:

Leviafan [203]3 years ago

3 0

Answer:

-50

Step-by-step explanation:

7 - (7 * 11 - 1) ÷ 2 - (5)² + 6

7 - (77 - 1) ÷ 2 - 25 + 6

7 - (76) ÷ 2 - 25 + 6

7 - 38 - 25 + 6

-31 - 19

-50

If my answer is incorrect, pls correct me!

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-Chetan K

natali 33 [55]3 years ago

3 0

B. $- 50$ ✅

Step-by-step explanation:

$7 - \frac{7 \times 11 - 1}{2} - ({5})^{2} + 6 \\ = 7 - \frac{77 - 1}{2} - 25 + 6 \\ = 13 - 25 - \frac{76}{2} \\ = - 12 - 38 \\ = - 50$

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Can someone help me? And no, I don’t just want the answer. I literally need to know how to do it pls

elena-s [515]

Answer:

Step-by-step explanation:

The angle b is a right angle which is divided into 2. So, each angle would measure 45 degree. (90 / 2 = 45)

tan 45 = 1

\AD\ = 100 - 64 = 36

to find x , remember SOCAHTOA

tan would be used because we have the vale of the opposite angle and we want to find the value of the adjacent angle

Tan 45 = opposite / adjacent

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7 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

8 0

3 years ago

Consider the graph shown. Which of the following does not represent the rate of change found when using similar triangles? Choos

Luba_88 [7]

Answer:

C and D

Step-by-step explanation:

since the line is going up from points A to D it cannot be a negative number.

have a nice day and mark me brainliest! :)

8 0

3 years ago

Choose the correct simplification of (4x3 + 3x2 − 6x) − (10x3 + 3x2).

Ray Of Light [21]

Answer:
-6x (x + 1)(x - 1)

Explanation:
Before we begin, remember the following:
(-ve) * (-ve) = +ve
(-ve) * (+ve) = -ve
(+ve) * (+ve) = +ve
(+ve) * (-ve) = -ve
a² - b² = (a + b)(a - b)

Now, for the given:
(4x³ + 3x² - 6x) - (10x³ + 3x²)
First, we eill remove the brackets based on the rules mentioned above. This will give us:
4x³ + 3x² - 6x - 10x³ - 3x²
Now, we will combine like terms as follows:
(4-10)x³ + (3-3)x² - 6x
-6x³ - 6x
Taking -6x as a common factor:
-6x (x² - 1)
Factoring the bracket as difference between two squares will give us the final simplest form:
-6x (x + 1)(x - 1)

Hope this helps :)

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4 years ago

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svp [43]

60. 5 cups equals 20 biscuits so 15 cups equals 60 biscuits

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3 years ago

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