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alexandr1967 [171]
3 years ago
6

HELPP I WILL GIVE BRAINLEIST!! PLSSSSS PLSSSSSSS

Mathematics
1 answer:
musickatia [10]3 years ago
8 0

Answer:

x = 3  &&  y = - 1

Step-by-step explanation:

Just solving the two equations

the first equation

y = 4/3 x +3

y  - 4/3 x = 3  ..............................................(1)

the second equation

y = -2/3x -3

y + 2/3 x = -3  ..............................................(2)

by substracting 2 from 1

-4/3x - 2/3x = -6

divide by -1

4/3x +2/3x = 6

6/3x = 6

2x = 6

x= 3

then subsititute by value x in any of given eqautions  

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<u>Figure</u><u> </u><u>:</u><u>-</u>

\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$}   \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}

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\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}

<u>On</u><u> </u><u>using</u><u> </u><u>this</u><u> </u><u>formula</u><u> </u><u>,</u><u> </u>

=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg)  \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}

8 0
3 years ago
Read 2 more answers
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