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PilotLPTM [1.2K]
3 years ago
7

If Steph Curry can shoot 72 free throws in 12 minutes, how many free throws

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

6

Step-by-step explanation:

you do 72÷12 and you get6

dimaraw [331]3 years ago
3 0
He can shoot 6 because at this point we are diving 72 divided by 12 equals 6 hope it helps
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Two positive integers have a sum of 17 and a product of 66. what are the integers?
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6 and 11.

6 + 11 = 17

6 × 11 = 66
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3 years ago
What is -2x^ -5x + 5 + 0 using quadratic formula
Mashutka [201]

Answer:

x = -5 + √65/2 or

x = -5 - √65/2

Step-by-step explanation:

-2x² - 5x + 5 = 0

2x² + 5x - 5 = 0

Here,

a = 2

b = 5

c = - 5

Now,

Discriminant

<em><u>D = b² - 4ac</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em>= (5)² - 4(2)(-5)

= 25 + 40

= 65

<u>D = 65 > 0</u>

Then,

x = -b +-√b² - 4ac/2a

x = -5 +-√(5)² - 4(2)(-5)/2(2)

= -5 +-√25 + 40/4

= -5 +-√65/4

= -5 +-√65/2

<em><u>x = -5 + √65/2 or x = -5 - √65/2</u></em>

6 0
3 years ago
A 4-foot tall child walks directly away from a 12-foot tall lamppost at 2 mph. How quickly is the length of her shadow increasin
xz_007 [3.2K]

Answer:

The length of the shadow is increasing with the rate of 1.5 feet per sec

Step-by-step explanation:

Let AB and CD represents the height of the lamppost and child respectively ( shown below )

Also, let E be a point represents the position of child.

In triangles ABE and CDE,

\angle ABE\cong \angle CDE    ( right angles )

\angle AEB\cong \angle CED  ( common angles )

By AA similarity postulate,

\triangle ABE\sim \triangle CDE

∵ Corresponding sides of similar triangles are in same proportion,

\implies \frac{AB}{CD}=\frac{BE}{DE}

We have, AB = 12 ft, CD = 4 ft, BE = BD + DE = 6 + DE,

\implies \frac{12}{4}=\frac{6+DE}{DE}

12DE = 24 + 4DE

8DE = 24

DE=3

Now, the speed of walking = 2 mph = \frac{2\times 5280}{3600}\approx 2.933\text{ ft per sec}

Note: 1 mile = 5280 ft, 1 hour = 3600 sec

Thus, the time taken by child to reach at E  

= \frac{\text{Walked distance}}{\text{Walking speed}}

=\frac{6}{2.933}

= 2.045 hours

Hence, the change rate in the length of shadow

= \frac{\text{Length of shadow}}{\text{Time taken}}

=\frac{3}{2.045}

= 1.5 ft per sec.

3 0
3 years ago
The values in the table represent a function. f(x) Use the drop-down menus to complete the statements. The ordered pair given in
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The answer would be
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