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aalyn [17]
3 years ago
7

Factors and common factors of 24,64,88

Mathematics
1 answer:
babunello [35]3 years ago
8 0
24- 1,2,3,4,6,8,12,24
64-1,2,4,8,16,32,64
88-1,2,4,8,11,22,44,88

Here are all the factors.^^
The common factors are 1,2,3,4,6
Hope this helps!
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Ne4ueva [31]

Given:

The equation is:

x=\ln 4

To find:

The equations that is equivalent to the given logarithmic equation.

Solution:

We have,

x=\ln 4

It can be written as:

e^x=e^{\ln 4}

e^x=4                  [\because e^{\ln x}=x]

Therefore, the correct option is D.

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Suppose the initial height of a Pumpkin is 12 feet and the pumpkin is being launched with a velocity of 61 feet per second. Use
iogann1982 [59]
<h2>Hello!</h2>

The answer is:

The maximum height before landing will be 69.7804 feet.

<h2>Why?</h2>

Since there is no information about the angle of the launch, we can safely assume that it's launched vertically.

So, we can calculate the maximum height of the pumpkin using the following formulas:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

v=vo-gt

Where,

y, is the final height

y_o, is the initial height

g, is the acceleration of gravity , and it's equal to:

g=32.2\frac{ft}{s^{2} }

t, is the time.

Now, we are given the following information:

y_{o}=12ft\\\\v=61\frac{ft}{s}

Then, to calculate the maximum height, we must remember that at the maximum height, the speed tends to 0, so, calculating we have:

Time calculation,

We need to use the following equation,

v=vo-gt

So, substituting we have:

v=61\frac{ft}{s}-32.2\frac{ft}{s^{2}}*t\\\\-61\frac{ft}{s}=-32.2\frac{ft}{s^{2}}*t\\\\t=\frac{-61{ft}{s}}{-32.2\frac{ft}{s^{2}}}=1.8944s

We know that it will take 1.8944 seconds to the pumpkin to reach its maximum height.

Maximum height calculation,

Now, calculating the maximum height, we need to use the following equation:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

Substituting and calculating, we have:

y=y_o+v_{o}*t-\frac{1}{2}gt^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}

y=12ft+61\frac{ft}{s}*1.8944s-\frac{1}{2}32.2\frac{ft}{s^{2}}*(1.8944s)^{2}\\\\y_{max}=12ft+115.5584ft-16.1\frac{ft}{s^{2}}*(3.5887s^{2})\\\\y_{max}=127.5584ft-57.7780ft=69.7804ft

Hence, we have that the maximum height before the landing will be 69.7804 feet.

Have a nice day!

3 0
3 years ago
If x - 1 = 5, what is the value of 8x - 8
Serggg [28]
X=6 is the answer to this equation
8 0
3 years ago
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PLz help awarding brainlest to best answer
Pie

Answer:

6, 5, 1, 7, 9, 2, 4, 8, 3.

Step-by-step explanation:

(from top to bottom, this should be right)

5 0
2 years ago
Read 2 more answers
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