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3 years ago

I need the volume of these two, please give me a quick answer. I don't have much time

Mathematics

2 answers:

madam [21]3 years ago

8 0

Answer:

1) V≈923.62824

2) V= 28.27433

alexandr1967 [171]3 years ago

6 0

Answer:

1. 923.16 or 294 Pi

2. 3052.08 or 972 Pi

Step-by-step explanation:

Formula for volume of a cone = Pi r^2 h/3

If diameter is 14, radius is 7

Pi 7^2 18/3

Pi 49 6

Pi 294

923.16

Formula for volume of a sphere = 4/3 pi r^3

If diameter is 18, radius is 9

4/3 pi 9^3

4/3 pi 729

972 pi

3052.08

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Alborosie

Answer:

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Step-by-step explanation:

√147 = 7√3

-8(7√3x)

-56√3x

4 0

1 year ago

At the building site there are 16 pallets with sacks of cement the total weight of all the pallets and cement is 4856 pounds eac

inysia [295]

The first thing we must do for this case is to define a variable.
We have then:
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3 years ago

NEED HELP ASAP GIVING BRANILEST

finlep [7]

Answer:

50?

Step-by-step explanation:

I said 50 because there were 60 na butterflies so there was probably 50.

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3 years ago

Read 2 more answers

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hoa [83]

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3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$

Let's plot a graph to see its interval . Graph attached in attachment .

Now we can see that the Interval notation of would be ,

$\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}$

<h3>Hence the standard form of inequality is y²+3y +2 ≤ 0 and the Solution set of the inequality is [ -2 , -1 ] .</h3>

4 0

2 years ago

I need the volume of these two, please give me a quick answer. I don't have much time​

I need the volume of these two, please give me a quick answer. I don't have much time