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goldfiish [28.3K]
3 years ago
11

Anyone know the answer to number 1 and 2?

Mathematics
1 answer:
lukranit [14]3 years ago
8 0

Answer:

1 is A

Step-by-step explanation:

2 is G

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Rewrite each expression by combining like terms. <br> 13p - 4p + 6q
Dovator [93]

Answer:

You answer would be 15p

Step-by-step explanation:

13p - 4p + 6p

9p + 6p

15p

7 0
3 years ago
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1. Estimate the area of the irregular shape. Explain your method and show your work.
wlad13 [49]

Answer:

31 square units

Step-by-step explanation:

See the picture below.

Each full or almost full square was counted first. There are 24 of them.

Then parts of squares of counted together to add to 1 square. They are color coded in the figure below. After adding them all up, the total was 31.

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3 years ago
Solve the following radical equation.<br>21*+2 - 18-3 = 18+9<br>x =​
stiks02 [169]

Answer:

x = -9, -2, and 3.

just set everything possible to 0.

since 0 = 0 it must be true.

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3 years ago
Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of y plus StartFraction one-hal
inn [45]

Answer:

y-2=3(x-3)

Step-by-step explanation:

We want to write the equation of a line in point-slope form.

This is given by:

y-y_1=m(x-x_1)

We have that line passes through (3,2).

Assuming the line has a slope of m=3, then the equation in point slope form is:

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3 years ago
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Calculate this reflection of the triangle:
Mice21 [21]

Answer:

a = 3, b = 0, c = 0, d = -2

Step-by-step explanation:

<em>To find the reflection Multiply the matrices</em>

∵ The dimension of the first matrix is 2 × 2

∵ The dimension of the second matrix is 2 × 3

<em>1. Multiply the first row of the 1st matrix by each column in the second matrix add the products of each column to get the first row in the 3rd matrix.</em>

2. Multiply the second row of the 1st matrix by each column in the second matrix add the products of each column to get the second row of the 3rd matrix

\left[\begin{array}{ccc}1&0\\0&-1\end{array}\right]  × \left[\begin{array}{ccc}0&3&0\\0&0&2\end{array}\right]  = \left[\begin{array}{ccc}(1*0+0*0)&(1*3+0*0)&(1*0+0*2)\\(0*0+-1*0)&(0*3+-1*0)&(0*0+-1*2)\end{array}\right]=\left[\begin{array}{ccc}0&3&0\\0&0&-2\end{array}\right]

Compare the elements in the answer with the third matrix to find the values of a, b, c, and d

∴ a = 3

∴ b = 0

∴ c = 0

∴ d = -2

7 0
4 years ago
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