Answer:

Step-by-step explanation:
Image of
is 
Image of
is 
Hence
corresponds to 
Distance from focus to vertex=distance from vertex to directix
from (6,2) to y=1, the distance is 1
the focus is 1/2 higher than the vertex
vertex=(6,1.5)
for
(x-h)^2=4p(y-k)
vertex=(h,k)
p=distance from vertex to directix
vertex=(6,1.5)
ditance=0.5
(x-6)^2=4(0.5)(y-1.5)
(x-6)^2=2(y-1.5) is the equation
or
y=0.5x^2-6x+19.5 or
y=0.5(x-6)^2+1.5
Answer:
Part a) The area of the swimming pool is 
Part b) The total area of the swimming pool and the playground is 
Step-by-step explanation:
Part a) Find the area of the swimming pool
we know that
The area of the swimming pool is

where
L is the length side
W is the width side
we have

substitute the values


therefore
The area of the swimming pool is 
Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground
we know that
To obtain the area of the playground multiply the area of the swimming pool by one and a half

To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground
so

therefore
The total area of the swimming pool and the playground is 
It goes to the opposing side of the circle, its a semicircle, or straight angle either way.