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oee [108]
3 years ago
5

In the town zoo 3/28 of the animals are birds of the birds for 4/15 are birds of prey what fraction of the animals at the zoo ar

e birds of prey
Mathematics
2 answers:
KIM [24]3 years ago
7 0
4/15 of 3/28....." of " means multiply

4/15 * 3/28 = 12/420 reduces to 1/35 <== birds of prey
Rudiy273 years ago
5 0

Answer:

\frac{1}{35}

Step-by-step explanation:

In this problem we have to multiply the fractions, because it says that \frac{3}{28} of the animals are birds, and from that fraction \frac{4}{15} are birds of prey. In other words, \frac{4}{15} of \frac{3}{28} are birds of the prey. One strategy to solve this quickly is remembering that "of" is translated into math language as multiplication, so:

\frac{3}{28} \frac{4}{15} = \frac{12}{420} =\frac{1}{35}

Therefore, \frac{1}{35} of the total birds, are birds of the prey.

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216 as it is the only one 6 divides into
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3 years ago
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PLEASE HELP ME WITH THIS QUESTION!! Thanks
Gre4nikov [31]

Answer:

20% probability

Step-by-step explanation:

First, we need to calculate the area of all the figures inside the rectangle.

Area of triangle= 1/2 BH

So, 3x2=(6)

Area of Square= L^2

3x3=(9)

Area of rectangle= LxW

=60.

60+9+6= 75.

75 is the total area.

Now, lets find the added area of only the triangle and square.

9+6= 15

The probability will be 15/75=

Convert into percent form

= 20%

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7 0
1 year ago
Carl spent $140 in six days. He spent $20 on the first day. He spent the same amount of money during the next five days Write an
grin007 [14]

Answer:

answer: he spent $120

Step-by-step explanation:

20×5=100

100+ the initial $20 spent = $120

8 0
2 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
3 to the power of 5 and (3) to the power of 5
Svetlanka [38]

Answer:

243

Step-by-step explanation:

3x3=9

9x3=27

27x3=81

81x3=243

6 0
3 years ago
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