A carrier (heterozygous) marries a pure normal skinned person, what is the probability they will have a child that is albino?

Biology

1 answer:

Morgarella [4.7K]2 years ago

4 0

Answer:

Explanation:

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Cross a parent that is homozygous recessive for both traits (bbee) with a dihybrid (BbEe). First, draw a Punnett square in your

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In this question, one parent is homozygous recessive (bbee) and other parent is dihybrid (BbEe)
B - black fur dominant trait
b - white fur recessive
E- black eyes dominant
e - red eyes recessive

a punnett square shows all the possible combinations of genotypes with the corresponding phenotypes that the offspring could inherit.
the genotypes and their phenotypes for the offspring are given below ;
BBEE / BbEe / BbEE / BBEe - black fur and black eyes
Bbee / BBee - black fur and red eyes
bbee - white fur and red eyes
bbEe / bbEE - white fur and black eyes

after analysing the punnett square the following results are obtained;
black fur and black eyes - BbEe- 4/16
black fur and red eyes -Bbee - 4/16
white fur and black eyes - bbEe - 4/16
white fur and red eyes -bbee - 4/16

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Explanation:

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