2 years ago

This problem just occured to me that i cant do welp time to ask for some help asap

Mathematics

1 answer:

sweet [91]2 years ago

8 0

Answer:

845

Step-by-step explanation:

Because they are similar triangles you can find the scale factor first.

395/553 is the scale factor

(395/553)*280=200

(395/553)*350=250

200+250+395 = 845

You might be interested in

One-half of the sum of a number and 6 is less than 25. What is the number

Leno4ka [110]

Answer:

Step-by-step explanation:

1/2(n + 6) < 25 Distribute

1/2n + 3 < 25

- 3 - 3 Subtract 3 from both sides

1/2n < 22 Multiply both sides by 2 or divide by 1/2

n < 44

If this answer is correct, please make me Brainliest!

4 0

3 years ago

The starting and stopping point for Amir’s run this morning are 0.5 inch apart on the map. If each inch on the map represents 3

Aleonysh [2.5K]

Amir ran 1.5 miles in the morning.

7 0

3 years ago

Read 2 more answers

A diver descended 45.98 feet in 12.1 minutes. What was the diver's average change in elevation per minute?

Kruka [31]

The answer should be 3.8

You can find this by dividing the total descent by the minutes the descent took

6 0

2 years ago

Write the equation of the parabola that has the vertex at point (2,-11) and passes through the point (0,5).

aleksandr82 [10.1K]

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\stackrel{vertex}{(\stackrel{h}{2}~~,~~\stackrel{k}{-11})}\qquad y=a(x-2)^2-11\qquad \qquad \textit{we also know that} \begin{cases} x=0\\ y=5 \end{cases} \\\\\\ 5=a(0-2)^2-11\implies 16=4a\implies \cfrac{16}{4}=a\implies 4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=4(x-2)^2-11~\hfill$

7 0

2 years ago

A triangle has vertices of (–2, –1), (0, –5), and (3, 2). What are the vertices of the image after applying the translation 2004

marysya [2.9K]

The triangle translated up would have vertices at S(1,4), T(2,0), and U(4,3).

7 0

3 years ago