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Whitepunk [10]
3 years ago
12

If you place 35 points on a piece of paper so that no three points are in a line, how many line segments are necessary to connec

t each point to all the others?
Mathematics
2 answers:
Ganezh [65]3 years ago
4 0
<span>Thank you for posting your Math question here at brainly. The line segments that are necessary to be connected to each point is 34. The total number of such connection is C(35,2) = 35 * 34/2. I hope the answer helps. </span>
bogdanovich [222]3 years ago
3 0

Answer:

595 line segments are necessary to connect each point to all the others.

Step-by-step explanation:

Consider the provided information.

The formula for the number of line segments between "n" non-collinear points is:

\frac{n\times ( n -1 )}{2} Segments

Here it is given that there are 35 points.

Substitute n = 35 in above formula.

\frac{35\times (35 -1 )}{2}

\frac{35\times 34}{2}

35\times 17

595 Segments

Hence, 595 line segments are necessary to connect each point to all the others.

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For the sake of example, let's multiply the two numbers 2.3 \times 10^5 and 3.5 \times 10^7 together. Altogether, we have:

2.3\times10^5\times3.5\times10^7

Rearranging the expression, we can group the exponents and coefficients together:

2.3\times3.5\times10^5\times10^7

Multiplying each out, we notice that since 10^5 and 10^7 have the same base (10), multiplying them has the effect of adding their exponents, which leaves us with:

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3 years ago
four times the sum of a number and 15 is at least 120. Let x represent the number. Find all possible values for x.
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The solution to the problem about the possible values of x in the inequality is as follows:

4(x+15) >= 120 
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3 years ago
A person filing her federal income tax return with the Single filing status had a taxable income of $79,950. According to the ta
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Answer:

The income that she will have left over after paying his

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Step-by-step explanation:

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