Answer:
The right answer is C
Step-by-step explanation:
Use the given values in the compound interest formula to solve for time, n.
A is the final amount of money, $2800
P is the initial or starting amount $1900
i is the interest rate as a decimal 0.025
n is time in years since it annual.
2800 = 1900(1 + 0.025)^n
2800 = 1900(1.025)^n
2800/1900 = (1.025)^n
28/19 = (1.025)^n
take the natural log of both sides to solve for exponent.
ln(28/19) = ln(1.025^n)
power rule of logarithmic moves exponent
ln(28/19) = n*ln(1.025)
ln(28/19) / ln(1.025) = n
put into a calculator
15.7 years = n
Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:


2.08
Now, we estimate standard deviation:


s = 0.1564
For t-score, we need to determine degree of freedom and
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
Answer:
Step-by-step explanation:



So let's say he was earring x before his raise. That means that:
x times 1.09 = 654 (1.09 represents 100% (this is the 1.0) of his original salary plus 9% (this is the .09) his raise.
So,
1.09x = 654; now divide both sides by 1.09 to isolate and solve for x, and you get x = $600.