To solve for the slope given two lines, use the formula:

(y₂ - y₁)
----------
(x₂ - x₁)

Set one of the points as (x₁, y₁), and the other as (x₂, y₂).

(x₁, y₁) = (0,32)
(x₂, y₂) = (100,212)

plug into corresponding places:

(y₂ - y₁) (212 - 32) (180)
---------- = -------------- = -------
(x₂ - x₁) (100 - 0) (100)

180/100 is your slope

If you want simplified, it will be: 9/5

hope this helps

5 0

3 years ago

Find the equation of the line passing through point (4,2) and perpendicular to AB

Setler [38]

Answer:

a. -⅓

b. 3

c. y = 3x - 10

Step-by-step explanation:

a. Gradient of line AB:

A(1, 3), B(7, 1)

$Gradient = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 3}{7 - 1} = \frac{-2}{6} = -\frac{1}{3}$

Gradient (m) = -⅓

b. The of the line that is perpendicular to line AB would be the negative reciprocal of the gradient of line AB.

Thus, the negative reciprocal of -⅓ = 3

Gradient of the line perpendicular to line AB = 3

c. Equation of the line that passes through (4, 2) and is perpendicular to line AB:

We can write the equation using the point-slope form equation, y - b = m(x - a), where,

(a, b) represents a point on the line, and,

m = gradient/slope

We know that the gradient/slope (m) = 3

Also, a point, (a, b) = (4, 2).

Therefore, substitute a = 4, b = 2, and m = 3 into y - b = m(x - a)

Thus:

y - 2 = 3(x - 4)

y - 2 = 3x - 12

Add 2 to both sides

y = 3x - 12 + 2

y = 3x - 10

5 0

3 years ago