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LekaFEV [45]
2 years ago
13

Quadrilateral A’B’C’D’ is a dilation of quadrilateral ABCD about point P. Quadrilateral ABCD is shown. Side AB is labeled 5. Sid

e BC is labeled 4. Side CD is labeled 10. Side DA is labeled 6. Quadrilateral A prime B prime C prime D prime is between quadrilateral ABCD and point P. Side A prime B prime is labeled 1 and one fourth. Side B prime C prime is labeled one. Side C prime D prime is labeled 2 and a half. Side D prime A prime is labeled 1 and a half. reduction enlargement

Mathematics
2 answers:
Stolb23 [73]2 years ago
5 0

Answer:  The correct option is (A) reduction.

Step-by-step explanation:  Given that the quadrilateral A'B'C'D' is a dilation of the quadrilateral ABCD.

As shown in the given figure, the lengths of the sides of quadrilateral ABCD are as follows:

AB = 5 units, BC = 4 units, CD = 10 units and DA = 6 units.

And, the lengths of the sides of quadrilateral A'B'C'D' are as follows:

A'B'=1\dfrac{1}{4}=\dfrac{5}{4}~\textup{units},~~B'C'=1~\textup{units},~~C'D'=2\dfrac{1}{2}=\dfrac{5}{2}~\textup{units},\\\\D'A'=1\dfrac{1}{2}=\dfrac{3}{2}~\textup{units}.

We know that the dilation will be an enlargement if the scale factor is greater than 1 and it will be a reduction if the scale factor is less than 1.

Now, the scale factor is given by

S=\dfrac{\textup{length of a side of the dilated figure}}{\textup{length of the corresponding side of the original figure}}\\\\\\\Rightarrow S=\dfrac{A'B'}{AB}=\dfrac{\frac{5}{4}}{5}=\dfrac{5}{4\times5}=\dfrac{1}{4}

Since the scale factor is less than 1, so the dilation will be a reduction.

navik [9.2K]2 years ago
5 0

Answer:

A reduction

Step-by-step explanation:

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Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N      Mass of the man,(m)= \frac{W}{g} = \frac{748}{9.8} = 76.32 kg

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Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is V_m .

Now using law of conservation of momentum we can find the V_m value.

m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)

Considering V_m_(_f_)=V_m

And initial velocity of both the man and book i.e V_b_(_i_)=0,\ V_m_(i_)=0

So,

⇒ 0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m

⇒ Plugging the values.

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⇒ V_m=-\frac{1.2\times 4}{76.32}

⇒ V_m=-0.062 ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, V_m = 0.062

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know velocity(v)\times time(t) = distance(d)

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⇒ t=\frac{4}{0.062}

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Identify a horizontal or vertical stretch or compression of the function f(x) = x by observing the equation of the function g(x)
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The vertical stretch of f(x) to g(x) is a factor of 5

<h3>How to determine the dilation?</h3>

The functions are given as:

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<h3>How to find the Mean Absolute Deviation?</h3>

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