Answer:
5.5 days (nearest tenth)
Step-by-step explanation:
<u>Given formula:</u>

= initial mass (at time t=0)- N = mass (at time t)
- k = a positive constant
- t = time (in days)
Given values:
= 11 g- k = 0.125
Half-life: The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.
To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

Therefore, the substance's half-life is 5.5 days (nearest tenth).
Learn more about solving exponential equations here:
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