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romanna [79]
3 years ago
12

(solve by substitution or elimination)Maci’s closet is a rectangle with a perimeter of 18 ft. Its length is 5 ft greater than it

s width.
Find the dimensions of her closet.
Mathematics
1 answer:
Greeley [361]3 years ago
8 0

Answer:2x7

Step-by-step explanation:2(x+5)+2x=18. 4x+10=18. x=2. 2x7.

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A grocer mixed walnuts worth $1.02 per pound with peanuts worth $0.99 per pound. If she made 69 pounds of a mixture worth $1 per
Nataly [62]
The cost of the mixture is $69 *$1 = $69. If all 69 pounds were peanuts, the cost would be 69*$0.99 = $68.31, which is $0.69 less. Each pound of walnuts used instead of peanuts adds $0.03 to the cost of the mixture, so there were $0.69/$0.03 = 23 pounds of walnuts. 
<span>_____ </span>
<span>Let w represent the number of pounds of walnuts in the mixture. Then 69-w is the number of pounds of peanuts. The cost of the mixture will be </span>
<span>1.02w + 0.99(69-w) = 1.00*69 dollars </span>
<span>0.03w + 68.31 = 69.00 </span>
<span>w = (69.00 - 68.31)/0.03 = 0.69/0.03 = 23</span>
6 0
3 years ago
You have a gift card worth $90. You want to buy several movies that cost $12 each. Write and solve an inequality that represents
DochEvi [55]
90-30>12 90-30=60 60/12= 5
8 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form when the y-intercept is 0 and the slope is -4​
PIT_PIT [208]

Answer: Y=mx+b

B is the y intercept and the slope is M

So the answer is Y= -4x+ 0

Step-by-step explanation:

7 0
3 years ago
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Find the horizontal and vertical asymptotes of​ f(x). ​f(x) equals = StartFraction 6 x Over x plus 2 EndFraction 6x x+2 Find the
miss Akunina [59]

Answer:

The horizontal asymptote can be described by the line y = 6

The vertical asymptote can be described by the line x = -2

Step-by-step explanation:

* <em>Lets the meaning of vertical and horizontal asymptotes</em>

- <u><em>Vertical asymptotes</em></u> are vertical lines which correspond to the zeroes

  of the denominator of a rational function

- <u><em>A horizontal asymptote</em></u> is a y-value on a graph which a function

 approaches but does not actually reach

- If the degree of the numerator is less than the degree of the

 denominator, then there is a horizontal asymptote at y = 0

- If the degree of the numerator is greater than the degree of the

 denominator, then there is no horizontal asymptote

- If the degree of the numerator is equal the degree of the denominator,

 then there is a horizontal asymptote at y = leading coefficient of the

 numerator ÷ leading coefficient of the denominator

* <em>Lets solve the problem</em>

∵ f(x)=\frac{6x}{x+2}

∵ The numerator is 6x

∵ The denominator is x + 2

∴ The numerator and the denominator have same degree

∵ The leading coefficient of the numerator is 6

∵ The leading coefficient of the denominator is 1

∴ There is a horizontal asymptote at y = 6/1

∴ <em>The horizontal asymptote can be described by the line y = 6</em>

- Put the denominator equal zero to find its zeroes

∵ The denominator is x + 2

∴ x + 2 = 0

- Subtract 2 from both sides

∴ x = -2

∴ <em>The vertical asymptote can be described by the line x = -2</em>

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME
Rama09 [41]

Answer:

y=x+11

Step-by-step explanation:

3 0
2 years ago
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