If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
Answer:

<em><u>Linear function :</u></em>The characteristic property of linear functions is that when the input variable is changed, the change in the output is proportional to the change in the input. Linear functions are related to linear equations.
Step-by-step explanation:
We have
y=mx+c
for 1st
not satisfied.
for
2nd
not satisfied
<em><u>3rd</u></em>
<em><u>3rd satisfied</u></em>
4th
[note : substitute value of x to get value of y from table]
so
<u>t</u><u>h</u><u>i</u><u>r</u><u>d</u><u> </u><u>table represents a linear function.</u>
Answer:
bc=eb and ca=fa
please tell me if this is actually the right answer
Step-by-step explanation:
bc=eb and ac=fa is wrong
bc=eb and ca=fa is right
cb=eb and ac=fa is wrong
ba=eb and ab=fa is wrong
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+
x=(-1)
Let x=0
y+
x=(-1)
y+
(0)=(-1)
y=(-1)
Let x=2
y+
x=(-1)
y+
(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)