Answer:
(7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance.
Step-by-step explanation:
We have a large sample size n = 56 research cotton samples. Besides, 
and 
. A 95% large-sample CI for the true average percentage elongation is given by 
, i.e., 
or equivalently (7.7981, 8.5419). The distribution of percentage elongation can be any distribution with finite mean and variance because we have a large sample.
Answer:
in point from: (-4,0) in equation from: x=-4,y=0
Step-by-step explanation:
Answer:
∠A: 98 (Is a vertical angle to the 98 degrees)
∠D: 151 (180-29)
∠H: 29 (Is a vertical angle to the 29 degrees)
∠I: 29
∠J: 151
∠M: 151 (Vert angle to <J)
∠R: 82 (180-98)
