Given side length "a" and angle "A", calculate the diagonals<span><span>
p = square root [( 2a^2 - 2a^2 cos(A) )]
</span>q = </span><span>square root [( 2a^2+ 2a^2 cos(A) )]</span>
http://www.calculatorsoup.com/calculators/geometry-plane/rhombus.php
side = 36
cos (32) = 0.84805
p = <span>small diagonal = </span>
<span>
<span>
<span>
19.8457652914
</span>
</span>
</span>
<span><span>
</span>
</span>
q =
large diagonal =
<span>
<span>
<span>
69.2108777578
</span>
</span>
</span>
After every drop,the ball bounces to half it's previous height. With that understood.
1st drop -The ball drops 10m
1st bounce - 5m up
2nd drop - 5m down
2nd bounce - 2.5m up
3rd drop - 2.5m down
3rd bounce - 1.25m up
4th drop - 1.25m down
4th bounce - 0.625m up
5th/last drop - 0.625m down
To find the total vertical distance, you add them all.
10+5+5+2.5+2.5+1.25+1.25+0.625+0.625
=29.25m travelled in all.
Answer:
The first one : decay
The second one : growth
When the argument of the exponential expression is bigger that 1 then it represents a growth
When it's less than 1 and above 0 then it's a decay
Answer:a. [tex] $f\propto L$ [\tex]
b. [tex] f \propto \sqrt{T} [\tex]
c. [tex] f \propto \frac{1}{\sqrt{P}} [\tex]
I. Decrease in length increases leads to increase in pitch.
II. Increase in tension leads to increase in pitch.
III. Increase in linear density reduces the pitch
Step-by-step explanation: I. Since the frequency is inversely proportional to the length increase in length leads to decrease in frequency likewise decrease in length leads to increase in frequency.
II. Since the frequency is directly proportional to the square root of the tension increase in tension leads to increase in frequency likewise decrease in tension leads to decrease in frequency.
III.since the frequency is inversely proportional to the square root of the linear density so increase in linear density leads to decrease in frequency and likewise decrease in linear density leads to increase in frequency.
Answer:
Whole number
Step-by-step explanation:
That's only because it is just 1 number that is gonna be there and i did some research too
