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d1i1m1o1n [39]
3 years ago
12

A student claims that the HCF/GCF/HCD/GCD of two numbers must be less than the two numbers. Do you agree? If not, give a counter

example to disproof it.
Mathematics
2 answers:
rusak2 [61]3 years ago
7 0

Answer:

what i don't understand

Step-by-step explanation:

Montano1993 [528]3 years ago
5 0

Answer:

No of course not

Step-by-step explanation:

For example, the GCF of 8 and 16 is 8. The GCF just has to be the greatest factor of both numbers, it doesn't have to be smaller.

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salantis [7]
So first subtract 20 from both sides of the equation.
3x-4=35
now add 4 to both sides.
3x=39
now divide both sides by
x=13
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4 years ago
What does difference of squares mean? How can you recognize it when looking at an expression?
ki77a [65]
It is called a difference of squares because there are two things squared being subtracted. You can recognize it when there are two terms, subtraction between the two of them, and you know the square root of both
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3 years ago
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An inch is equal to about 2.54 centimeters. Write an expression who he estimates the number of centimeters in x inches. Then est
trasher [3.6K]

There are 30.48 centimeters in 12 inches.

Step-by-step explanation:

Given,

1 inch = 2.54 centimeters

For x inches;

x inches = 2.54*x centimeters

x inches = 2.54x centimeters

Number of centimeters in 12 inches

We will put x=12

12 inches = 2.54(12) centimeters

12 inches = 30.48 centimeters

There are 30.48 centimeters in 12 inches.

Keywords: multiplication

Learn more about multiplication at:

  • brainly.com/question/10744457
  • brainly.com/question/10754198

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5 0
4 years ago
What are the solutions of the equation x4+3x2+2=0? use u substitution to solve
sweet [91]

Answer: x = ± i , x = ±√2i are solution .

Step-by-step explanation:

Given : x^{4} +3x^{2} +2=0, use u substitution to solve.

To find : what are the solutions of the equation .

Solution : We have given that x^{4} +3x^{2} +2=0.

Let consider x^{2} = u .

Substitute u =  x^{2} in given equation .

u^{2} + 3u +2=0.

On factoring

u^{2} + 2u+1u +2=0.

Taking common

u( u+2) +1 (u+2) = 0.

On grouping

(u+1) (u+2) =0

Now, u+1 = 0 ⇒ u = -1.

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In term of x, plugging x^{2} = u.

x^{2} = -1   ;  x^{2} = -2.

taking square root both side

x = ± i

x = ±√2i.

Therefore, x = ± i , x = ±√2i are solution .

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