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Katyanochek1 [597]
3 years ago
14

Write the equation of the hyperbola whose center is at the origin and has a vertical transverse axis. The equations of the asymp

totes are 6x+2y=0 and 6x-2y=0.
Mathematics
1 answer:
zzz [600]3 years ago
6 0
 <span>I'll tell you the rule first: 

The general form of the hyperbola having a vertical axis and centered at the origin is: 

(y/a)^2 ‑ (x/b)^2 = 1 

Asymptotes: 

y= ±(a/b)x 

Or (y/a)^2 - (x/b)^2 = 0 

So in your problem the asymptotes are: 

2y ± 6x = 0 

2y = ±6x 

y = ±(3/2)x 

So, a=3 b=2 

The equations are: 

(y/3)^2 - (x/2)^2 = 1 

(y^2)/8 - (x^2)/4 = 1 


Hope it helps you.</span>
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3 years ago
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Help me make it simple C=cos25°cos35°-cos65°cos85°​
nikdorinn [45]

Answer:

It invaluatesa to 1

Step-by-step explanation:

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hope this helped you!

4 0
3 years ago
Does anyone know the answer to this?
VARVARA [1.3K]

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6 0
3 years ago
Is it wise for a firm to employ a worker at $20 per hour when another worker does the same job for $10 per hour?
vekshin1
<span>For me,

It would be a rational decision if the first worker was more than twice as productive as the second worker.</span>

This can happen in real life, for example 2 workers are hired to do the same type of job but one worker graduated with honors, the company can give a higher pay to the worker with honors compared with the other one who graduated. 

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4 years ago
Which algebraic expression is a polynomial? 4x2 – 3x + StartFraction 2 Over x EndFraction –6x3 + x2 – StartRoot 5 EndRoot 8x2 +
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Answer:

Step-by-step explanation:

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5 0
3 years ago
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