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Yuri [45]
4 years ago
12

4. find the real number roots. sqrt-0.25

Mathematics
2 answers:
e-lub [12.9K]4 years ago
3 0

Given is square root of a negative real number, i.e. \sqrt{-0.25}

When we find square root of positive real numbers, we get Real answers.

But when we find square root of negative real numbers, we get Imaginary answers. To solve them, we can split the given negative number into product of -1 and the number itself but with positive sign. e.g. -4 = -1 x 4.

For square root of -1, we use english letter 'i' called Imaginary unit i.e. \sqrt{-1} = i

Now we can use -0.25 = -1 x 0.25

\sqrt{-0.25} =\sqrt{-1*0.25} \\\\ \sqrt{-0.25} =\sqrt{-1}*\sqrt{0.25} \\\\ \sqrt{-0.25} =i*0.5 \\\\ \sqrt{-0.25} =0.5i

Hence, "0.5i" is the final answer.

Kitty [74]4 years ago
3 0
You can find real numbers root. It would be Undefined
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I NEED HELP!!!!
Finger [1]

Step-by-step explanation:

So Scientific Notation is like this.

Ya got a big number that has of 0s . Let's just throw out 69,000,000,000,000

You take the other numbers that arent 0s. Take the first number and put a "." in between it and the second number. So, in this case, you have 6.9, like this.

You then count the number of 0s and +1. So in this case, you'll have 12+1. Which is 13.

You then take the 6.9 and note it with a *10. You then take the 13 and put it on the 10 as an exponent. So in the end youll have 6.9*10^13.

Hopefully, this helps.

<em>With love,</em>

<em />

<em>A G 4 2</em>

3 0
3 years ago
What is 175.42 rounded to the nearest tenth?
weqwewe [10]
175.4 because 4 is the tenth place and 2 would round down
4 0
3 years ago
P+8.94/3 = 3.82 whats p
skad [1K]

Answer:

p=.84

Step-by-step explanation:

p=8.94/3=3.82

p+2.98=3.82

p=.84

3 0
3 years ago
Helpplsssssssssssssss number 2
IceJOKER [234]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Consider a propeller driven aircraft in forward flight at a speed of 150 mph: The propeller is set up with an advance ratio such
meriva

a)  The thrust of the propeller is  23,834 lbf

b)  The induced velocity is 8.44 mph

c)  The velocity in the downstream far field away from the propeller disc     is 161.56 mph

d) The power absorbed by the fluid is  42.7 hp

e)  the propeller power (thrust flight speed) is  4,844.08 hp

f)  The propeller efficiency is 113.6%

a)The thrust of the propeller can be calculated using the equation,

Thrust = 2πρR^2V^2, where ρ is the air density, R is the propeller radius, and V is the average velocity of the propeller disc. For sea level at a speed of 150 mph, the air density is about 0.002377 slugs/ft^3.

the thrust of the propeller can be calculated as: Thrust = 2π x 0.002377 x (6 ft)^2 x (170 mph)^2 = 23,834 lbf

b)The induced velocity can be calculated using the equation v_ind = (1/2) V ∞ [1–(V_∞/V_tip)^2]^(1/2), where V_∞ is the free stream velocity and V_tip is the tip velocity of the propeller. For the given problem, the induced velocity can be calculated as: v_ind = (1/2) x 150 mph x [1–(150 mph/170 mph)^2]^(1/2) = 8.44 mph

c) The velocity in the downstream far field can be calculated using the equation V_∞ = V_tip – v_ind, where V_tip is the tip velocity of the propeller and v_ind is the induced velocity. For the given problem, the velocity in the downstream far field can be calculated as: V_∞ = 170 mph – 8.44 mph = 161.56 mph

d)The power absorbed by the fluid can be calculated using the equation P_fluid = (1/2) ρ V_ind^3 A_disc, where ρ is the air density, V_ind is the induced velocity, and A_disc is the area of the propeller disc. For the given problem, the power absorbed by the fluid can be calculated as P_fluid = (1/2) x 0.002377 x (8.44 mph)^3 x (π x (6 ft)^2) = 42.7 hp

e)The power absorbed by the propeller can be calculated using the equation P_prop = T x V, where T is the thrust of the propeller and V is the flight speed of the aircraft. For the given problem, the power absorbed by the propeller can be calculated as: P_prop = 23,834 lbf x 150 mph = 3,575,500 ft-lbf/s = 4,844.08 hp

f)The efficiency of the propeller can be calculated using the equation η = P_prop/P_fluid, where P_prop is the power absorbed by the propeller and P_fluid is the power absorbed by the fluid. For the given problem, the efficiency of the propeller can be calculated as: η = 4,844.08 hp/42.7 hp = 113.6%

To know  more  about induced velocity refer to the link brainly.com/question/15280442

#SPJ4

8 0
1 year ago
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