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Varvara68 [4.7K]
3 years ago
7

YEAR 9 MATHS

Mathematics
2 answers:
Alex3 years ago
8 0

Answer:

(2,1)

Step-by-step explanation:

up the corridor and down the stairs!

Lady bird [3.3K]3 years ago
4 0
Small triangle : (1,4), (3,1), (3,4)
The x: (3,2)
The big triangle: (-3,3), (-1,5), (-2,1)

(For the big triangle that is only correct if the black dot is the mirror line)
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Can someone please explain this
S_A_V [24]
Oh. It's rounding. So, for example, depending what you were told to round to, the second problem would be 760-330=430
7 0
3 years ago
charity is four times as old as her daughter. she is also six years younger than her husband. The sum of their ages ten years to
Pachacha [2.7K]

Answer:

36years

Step-by-step explanation:

Let charity present age be x

Charity daughter present age be y

Charity husband present age be z

If the sum of their ages ten years to come is 117, then;

10+x+10+y+10+z = 117

30+x+y+z = 117

x+y+z = 87 ... 1

If charity is four times as old as her daughter, then;

x = 4y

y = x/4 ... 2

If she is also six years younger than her husband, then;

x = z- 6

z = x+6 .. 3

Substitute 2 and 3 into 1;

x + x/4 + (x+6) = 87

Multiply through by 4

4x + x + 4(x+6) = 4(87)

5x+4x+24 = 348

9x = 348 - 24

9x = 324

x = 324/9

x = 36

hence Charity is 36years old today

5 0
3 years ago
Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

7 0
3 years ago
5,900 round to the nearest thousand
Karo-lina-s [1.5K]
The answer is six thousand
3 0
3 years ago
Simpiflying 4 5/8 and 3 3/8 subtraction<br><br>​
denis-greek [22]

Answer:

It is 5/4

Step-by-step explanation:

7 0
3 years ago
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