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artcher [175]
3 years ago
13

Use ELIMINATION: 2x - 6y = -54 X + 6y = 63

Mathematics
1 answer:
dybincka [34]3 years ago
6 0
(5,-1) is the correct answer for this question
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Original price $90 markdown 24%​
Gre4nikov [31]
The markdown will be $21.60. so the final price after the markdown is $68.40.
8 0
3 years ago
What is 105,159 rounded to the nearest ten thousand
ludmilkaskok [199]
The answer will be 100,000 I hoped this helped;)
3 0
3 years ago
Read 2 more answers
I need the answer to a parts I-iii and the answer to b
fomenos

Answer:

a)

i) Mean = 72

ii) Median = 72

iii) Mode = 72

b)

69, 70, 71, 72, 72, 72, 73, 74, 75

Step-by-step explanation:

<u>a. To find mean, median and mode</u>

It is given that all the 9 students get 72 marks.

Therefore the data set be,

72, 72, 72, 72, 72, 72, 72, 72 72

<u>i) mean </u>= (sum of data)/(total number of data)

 = (9 * 72)/9 = 9

<u>ii) Median </u>- Central data in the data set when arranging ascending or descending order

72, 72, 72, 72, 72, 72, 72, 72 72

Median = 72

<u>iii) Mode </u>- Most repeating data in the data set

Here mode = 72

<u>b). To find a data set</u>

69, 70, 71, 72, 72, 72, 73, 74, 75

Here Mean, mode and median are all 72

3 0
4 years ago
3. Which is the better buy?
Olegator [25]

Answer:

3.49 for 8 candles

Step-by-step explanation:

2.99/6=.49833

4.49/9=.49888

5.99/12=.49916

3.49/8=.43625

5 0
3 years ago
Read 2 more answers
In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?
erica [24]

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

BD = c*sin(A)

BD = c*cos(B)

BD = b*tan(A)

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

sin(A) = \frac{x}{c}

Make x the subject of formula.

c*sin(A) = x

BD = x = c*sin(A)

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

cos(B) = \frac{x}{c}

Make x the subject of formula.

c*cos(B) = x

BD = x = c*cos(B)

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

tan(A) = \frac{x}{b}

Make x the subject of formula.

b*tan(A) = x

BD = x = b*tan(A)

5 0
3 years ago
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