Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
-30/49 would be my answer to this. hope this helps!
Add the fractions together
1/7 + 1/2
find a common denominator
1/14 + 1/14
= 2/14 + 7/14
= 9/14
X=21
This is because both of those angles are equal, so you would divide 42 by 2 and get 21
First, change the measurements of the pole to m so all of the units are the same.
41 cm=.41 m
72 cm=.72 m
Then, let x represent the height of the building
30/x=.72/.41
x=30*.72/.41
x=52.68 m
round to 52.7 m
