Given the rhombus, find x and y Please help!!

Mathematics

2 answers:

NeX [460]3 years ago

7 0

Your answer would be Y=158 X=22

Leno4ka [110]3 years ago

5 0

Answer:

we know that, the point where the diagonals meet creates angles and these angles can indeed sum upto 360 degrees. and these angles, most likely are 90 degrees, since 90+90+90+90=360 degrees.( and the diagonals of a rhombus meet at approximately right angles)

lets take a triangle out of the rhombus, ( the triangle with angle 22)

here, we have two angles, 22 degrees and 90 degrees( angle at the diagonals); we also know that interior angles of a triangle is 180 degrees.

so, 22+90+unknown = 180 degrees

112+ unknown=180

unknown = 180 -112

= 68 degrees

we have found that the angle next to x is 68 degrees and that interior angles of the rhombus is 360, which means that each interior angle sums upto 90 degrees. lets take the angle beside x as z. since we have found that z= 68 degrees, 90-68 degrees gives x which is 22 degrees.

so, x= 22 and y= 90

You might be interested in

Please help me it’s almost due

Serhud [2]

I believe the answer is C

7 0

3 years ago

-0.85 - (-¼) + 0.4 + (-⅖) ?<br> what is the value of the expression?

drek231 [11]

Answer: =−3/5

Step-by-step explanation: Hope this help :D

6 0

2 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$