How is .8333 as a fraction 5/6?

Triangle ABC is similar to triangle DEF. what is the value of x ? Pic attached :) thank you.

vodomira [7]

X=6 and 2/3
the proportion is also 3:5

6 0

3 years ago

Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

3 0

3 years ago

Graph the line with the slope -3/4 passing through the point (4,-1)

-Dominant- [34]

Answer:

Step-by-step explanation:

Plot the point (4, -1) in the 4th Quadrant.

The slope (-3/4) tells us what to do next:

With your pencil point initially on (4, -1), move it 4 units to the right, to (8, -1).

With your point initially on (8, -10, move it down 3 units, to (8, -4). Plot (darken) (8, -4).

Draw a line through (4, -1) AND (8, -4)

7 0

3 years ago

Number bond to make hundred write simplified equation and solve 190+ 460=

Radda [10]

I think that would be 650

4 0

3 years ago

Read 2 more answers

Cube shaped boxes of tissues are shipped to stores in containers. The containers are rectangular prisms. The edges of each tissu

miskamm [114]

I will first calculate the volume of the tissue boxes, that are cubes.

Volume = Base Area x Height

The base area of a cube is a square so:
Base Area (Square) = L^2

In the cube, all sides have the same measure so the height is also L.

L = 6.5 in

Volume (Cube) = L^2 x L = L^3
-> Volume (Cube) = (6.5)^3
-> Volume (Cube) = approximately 275 in^3

Now calculate the Shipping Container volume:
*Represented on the photo, sorry for the bad drawing

The shipping container is a rectangle prism, every rectangle prism have on the base a square, and a square must have every sides with the same measure, knowing that, we know that the two 19.5 inches measures in the question is the length and width of the square. And the 39 inches measure is the Height of the prism.

Base Area (Square) = L^2 = (19.5)^2 = 380,25 in^2 = approx. 380 in^2
Height = 39 in

Volume = Base Area x Height
-> Volume (Prism) = 380 x 39 = 14,820 in^3

Now, to find the greatest number of tissue boxes (cubes) that fit into one container, you just need to divide the container volume by the cube volume and the quotient will be the number of tissue boxes into the container.

Cube's Volume = 275 in^3
Rectangular Prism's Volume = 14,820 in^3

$14820 \div 275 = 53.8909....$
Answer: 53 tissue boxes.

5 0

3 years ago