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sergey [27]
3 years ago
13

Which of the following does not describe behavior that demonstrates financial responsibility?

Mathematics
1 answer:
zysi [14]3 years ago
7 0

Answer:

you didn't show the following

Step-by-step explanation:

but I'd love to help

You might be interested in
Don’t need to send the math or anything just need the answer will give brainliest!!!
svp [43]

Answer:

920

Hope that this helps!

6 0
3 years ago
How do you prove each of the following theorems using either a two-column, paragraph, or flow chart proof?
lilavasa [31]

All the theorems are proved as follows.

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three vertices and three angles.

1. The Triangle sum Theorem

According to the Triangle Sum Theorem, the sum of a triangle's angles equals 180 degrees.

To create a triangle ABC, starting at point A, move 180 degrees away from A to arrive at point B.

We turn 180 degrees from B to C and 180 degrees from C to return to A, giving a total turn of 360 degrees to arrive to A.

180° - ∠A + 180° - ∠B + 180° - ∠C = 360°

- ∠A - ∠B  - ∠C = 360° - (180°+ 180°+ 180°) = -180°

∠A + ∠B  + ∠C = 180°

(Hence Proved)

2. Isosceles Triangle Theorem

Considering an isosceles triangle ΔABC

with AB = AC, we have by sine rule;

\rm \dfrac{sinA}{BC} =  \dfrac{sinB}{AC} =  \dfrac{sinC}{AB}\\

as AB = AC

sin B = sin C

angle B = angle C

3.Converse of the Isosceles theorem

Consider an isosceles triangle ΔABC with ∠B= ∠C, we have by sine rule;

\rm \dfrac{sinA}{BC} =  \dfrac{sinB}{AC} =  \dfrac{sinC}{AB}\\

as  ∠B= ∠C ,

AB = AC

4. Midsegment of a triangle theorem

It states that the midsegment of two sides of a triangle is equal to (1/2)of the third side parallel to it.

Given triangle ABC with midsegment at D and F of AB and AC respectively, DF is parallel to BC

In ΔABC and ΔADF

∠A ≅ ∠A

BA = 2 × DA, BC = 2 × FA

Hence;

ΔABC ~ ΔADF (SAS similarity)

BA/DA = BC/FA = DF/AC = 2

Hence AC = 2×DF

5.Concurrency of Medians Theorem

A median of a triangle is a segment whose end points are on vertex of the triangle and the middle point of the side ,the medians of a triangle are concurrent and  the point of intersection is inside the triangle known as Centroid .

Consider a triangle ABC , X,Y and Z are the midpoints of the sides

Since the medians bisect the segment AB into AZ + ZB

BC into BX + XB

AC into AY + YC

Where:

AZ = ZB

BX = XB

AY = YC

AZ/ZB = BX/XB = AY/YC = 1

AZ/ZB × BX/XB × AY/YC = 1 and

the median segments AX, BY, and CZ are concurrent (meet at point within the triangle).

To know more about Triangle

brainly.com/question/2773823

#SPJ1

8 0
2 years ago
What can you say about the marked angles?
Vesnalui [34]
The angles look like

F
F- angles are corresponding angles.

Corresponding angles are congruent.

The correct answer is A
6 0
3 years ago
Please help!!!!!!!!!!!
Assoli18 [71]

<u>Let's take this problem step by step:</u>

<u>To find the ordered pair of the system:</u>

⇒ must set both equations equal to each other

    ⇒ and solve for 'x'

<u>Let's solve:</u>

 x^2-2x+3=-2x+19\\x^2-2x+2x+3-19=0\\x^2-16=0\\(x+4)(x-4)=0

<u>Let's find the x-values:</u>

   (x-4)=0\\x=4\\\\(x+4)=0\\x=-4

<u>Let's find f(x)'s value for each 'x':</u>

 x=4\\f(4)=-2(4)+19=-8+19=11\\\\x=-4\\f(-4)=-2(-4)+19=8+19=27

<u>Answer: (4, 11), (-4,27)</u>

Hope that helps!

#LearnwithBrainly

3 0
2 years ago
Find the circumference of a circle whose area is 24pi ft^2
Vsevolod [243]
Area = 24pi ft^2 = pi * r^2
This gives r = root24


Circumference = 2pi * r
= 2pi * root24
= 4pi * root6


Hope I'm able to help you.
6 0
3 years ago
Read 2 more answers
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