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2 years ago

0.006 A= _____ mAhelp me,,,,

Mathematics

2 answers:

BARSIC [14]2 years ago

8 0

Answer:6 mA

Step-by-step explanation:hope this helps :)

Digiron [165]2 years ago

7 0

0.006A = 6 mA

The answer is 6

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The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

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2 years ago

Find the amount in an account where $500 is invested at 2.5% compounded continuously for period of 10 years

Alex17521 [72]

500 *1.025^10 ≈ 640.04

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3 years ago

2 345 000 000 in scientific notation

grigory [225]

2.345 * 10^9 . Hope this helps

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3 years ago

On a town map, each unit of the coordinate plane represents 1 mile. Three branches of a bank are located at A(−3, 1), B(1, 4), a

Juli2301 [7.4K]

The distance between Branch A and Branch B is given by the Pythagoras theorem

AB² = (Vertical Distance)² + (Horizontal Distance)²
AB² = (4-1)² + (1 - -3)²
AB² = 3² + 4²
AB² = 9 + 16
AB² = 25
AB = 5

BC² = (Vertical distance)² + (Horizontal distance)²
BC² = (-2 - 4)² + (5-1)²
BC² = (-6)² + (4)²
BC² = 36 + 16
BC² = 52
BC = 7.21

Half way of BC = 7.21 ÷ 2 = 3.6 miles

Total distance travelled from A to B and then halfway from B to C is 3.6+5 = 8.6 miles

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3 years ago

You need to be at least 39.37 inches tall (about a meter) to ride on a bumper car. Diego’s cousin is 35.75 inches tall. How many

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39.37-35.75=3.62

3.62 inches

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2 years ago

0.006 A= _____ mAhelp me,,,,​

0.006 A= _____ mAhelp me,,,,