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coldgirl [10]
3 years ago
9

Are these ratios equivalent?

Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

3:9 in their lowest forms are 1:3 which is the same for 6:18

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You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte
Mama L [17]

Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \,  otherwise }} \right.

a)  We calculate  the probability that you need less than 5 minutes to get up:

P(x

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate  the probability that you will need between 8 and 13 minutes:

P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

Therefore, the probability is P(8<x<13)=0.3.

d)  We calculate the probability that you will be late to each of the 9:30am classes next week:

P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

You have 9:30am classes three times a week.  So, we get:

P=0.6^3=0.216

Therefore, the probability is P=0.216.

e)  We calculate the probability that you are late to at least one 9am class next week:

P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1

Therefore, the probability is P=1.

3 0
3 years ago
What should be added to twice a rational Number -7/3to get 3/7<br>​
saul85 [17]

Answer:

107/21

Step-by-step explanation:

re - phrase the question algebraically:

-14/3 + y = 3/7

LCM of 3 and 7  = 21

-98/21 + y = 9/21

what should be added to -98 to make 9?

answer: 107

therefore answer: 107/21

Hope this helps.

Good Luck

3 0
3 years ago
Write an algebraic expression for the phrase the product of 4 and s.
notka56 [123]

Answer: 4s

Step-by-step explanation:

Product means multiply

4 times s = 4s

8 0
3 years ago
Read 2 more answers
Two cyclists leave city at same time, one going east and the other going west. The westbound cyclist bikes 3 mph faster than the
Bumek [7]

Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.

<u>Solution:</u>

Let us assume that x is speed of slower eastbound cyclist

So, x+3 will be the speed of faster westbound cyclist

We know that distance is the product of speed and time. That is,

\text{Distance}=\text{Speed}\times\text{Time}

West-bound DATA:

Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles

East-bound DATA:

Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles

On solving,

Distance apart = 162

\Rightarrow6x+18+6x = 162

\Rightarrow12x=162-18

\Rightarrow x=\frac{144}{12}\rightarrow x=12

So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be x+3=12+3=15 \text{ mph}

8 0
2 years ago
I don’t know if it’s wrong or not
faltersainse [42]
I actually think that it is 50
5 0
3 years ago
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