Answer:
a) we have the numbers 0, 2, 3, 5, 5. The mean and the median are both 3
b) we have the numbers 0, 0, 3, 5, 7. The mean and the median are both 3
In both cases the mean and the median are 3, but the mode differs. The mean and the median do not uniquely determine the mode.
Step-by-step explanation:
A= 9 b= 224
Just add them to find ur anwser make sure to get these
<span>3(2x+4y-2z)+7(x+y-4z) =
3*2x + 3*4y - 3*2z + 7x + 7y - 7*4z =
6x + 12y - 6z + 7x + 7y - 28z =
(6+7)x + (12+7)y + (-6-28)z =
13x + 19y + (-34)z =
13x + 19y -34z;
</span>
9514 1404 393
Answer:
(a) an = -4·2^(n-1)
Step-by-step explanation:
The form for the general term is ...
an = a1·r^(n-1) . . . . . a1 is the first term; r is the common ratio
For a1=-4 and r=-8/-4 = 2, the rule will be ...
an = -4·2^(n-1)
Answer:
I know you could easily solve this just looking at it.
But if you want the algebraic solution:
x + x^2 = 30
x^2 + x -30 = 0
a = 1
b = 1
c = -30
Using the quadratic formula:
x = [ -b +- sqr root (b^2 - 4ac) ] / 2a
x = [-1 +- sqr root (1 - 4 * 1 -30) ] / 2*1
x = [-1 +- sqr root (1 + 120) ] / 2
x = -1 +- sqr root (121) / 2
x1 = (-1 + 11) / 2 = 10 / 2 = 5
x2 = (-1 -11) / 2 = -12 / 2 = -6
Answers are 5 and -6
5 + 5^2 = 30
-6 + (-6)^2 = 30
-6 +36 = 30
Step-by-step explanation:
