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3 years ago

If a fraction is equal to 2/9

Mathematics

1 answer:

Illusion [34]3 years ago

7 0

Answer:

18/81

Step-by-step explanation:

the current fraction adds up to 11 so to get 99 you would need to multiply both the numerator and the denominator by 9 to get a sum of 99

so 2 x 9 = 18 and 9 x 9 =81

so answer is 18/81

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What value does the 2 represent in the number 52.3?

Vsevolod [243]

Answer:

2 in 52.3

Step-by-step explanation:

the two in 52.3 represents 2

4 0

4 years ago

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Emily has a lock that uses the numbers 0-7. The combination is 3 numbers long. What is the probability that the combination is 7

Margarita [4]

333 most likely then

8 0

4 years ago

The speed limit on a road in Canada is 70 kilometers per hour. What is this speed in miles per hour?

Lera25 [3.4K]

Answer:

43.496

Step-by-step explanation:

When going from kilometers to miles, divide the length in kilometers by 1.609. When we do that, we get 43.496.

6 0

3 years ago

If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=

Alexxx [7]

$\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\$

$\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}$

now, if we just knew what g(2) is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that means if we use that value in f(x), f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus 2 = 2x+sin(x)

$\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}$

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it

5 0

3 years ago

In a random sample of 535 people 65% said they like cookies with chocolate chips 37% like cookies with peanut butter chips. 25%

Leokris [45]

<h3>The probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.</h3>

Step-by-step explanation:

Here, the total sample of people has total 535 people.

The percentage of people liking chocolate chip cookies = 65%

Now, 65% of 535 = $\frac{65}{100} \times 535 = 347.75 \approx 348$

⇒ 348 people in total like chocolate chip cookies.

⇒ n(C) = 348

The percentage of people liking peanut butter chip cookies = 37%

Now, 37% of 535 = $\frac{37}{100} \times 535 = 197.95 \approx 198$

⇒ 198 people in total like peanut butter chip cookies.

⇒ n(B) = 198

Percentage of people liking both chocolate &peanut butter chips = 25%

Now, 25% of 535 = $\frac{25}{100} \times 535 =133.75 \approx 134$

⇒ 134 people in total like both chocolate &peanut butter chips

⇒ n(C ∩ B ) = 134

Now, n( C U B) = N(C) + n(B) - n(C ∩ B )

= 348 + 198 - 134 = 412

P( person likes cookies with chocolate or peanut butter chips)

= $\frac{\textrm{person likes cookies with chocolate or peanut butter chips}}{\textrm{Total People}} = \frac{412}{535} = 0.77$

Hence, the probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.

6 0

3 years ago