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Makovka662 [10]
3 years ago
12

20 lb >, < , =304 OZ

Mathematics
1 answer:
KengaRu [80]3 years ago
7 0
The answer is >

304 oz is equal to 19 lb.
20>19
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January, Scott earned $8,999. In February, he earned $2,387 more than in January. In March, Scott earned the same amount as in F
netineya [11]

Answer:I believe it's 31,771

Step-by-step explanation: you first need to add 8,999 + 2,387 to get 11,386 then add 11,386 + 11,386 to get 22,772 and then add 8,999 to get 31,771.

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3 years ago
Which ordered pair is a solution of the equation? <br>equation (-4x+7=2y-3)
Greeley [361]

Answer:

Its Option C.

Step-by-step explanation:

-4x + 7 = 2y - 3

Substitute the given values in the  given equation:-

(2,1):-    -4(2) + 7 = -1  and 2(1) - 3 = -1  so (2,1) is a solution.

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−3x−3y=6. What is the slope
Alinara [238K]

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Step-by-step explanation:

slope = -1

6 0
3 years ago
Help me figure this out please
Ulleksa [173]

Answer:

the answer is A

Step-by-step explanation:

b and d are wrong based on the first part of the polynomial being of a low value (3x^10 is highest) and c is wrong based on the fact that 2x^2 is higher than x^6.

8 0
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In a given course a student receives preliminary examination grades of 81, 85, and 95. The final examination is weighed for one-
Vsevolod [243]

Answer:

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Step-by-step explanation:

Let x represent score of final third exam.

We have been given that in a given course a student receives preliminary examination grades of 81, 85, and 95.

Let us find average of preliminary scores.

\frac{81+85+95}{3}=\frac{261}{3}=87

We have been given that the final examination is weighed for one-third and the average of the preliminary grades is weighed as 2/3 of the final grade. This means that final grade is equally weighed into 3 parts. The two parts are 87 each and third part is x.

Using our given information, we can set an equation as:

\frac{87+87+x}{3}=90

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\frac{174+x}{3}*3=90*3

174+x=270

174-174+x=270-174

x=96

Therefore, the final examination grade should be 96 for a semester average of 90.

4 0
3 years ago
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