Answer:
How far did the ship travel between the two observations of the lighthouse = 9.29
Step-by-step explanation:
the first step to answer this question is drawing the illustration as the attachment.
P is the ship, R is the light house and Q is the bearing.
PR is the distance between the ship and the light house, PR = 10.5
∠P = 42.8°, ∠Q = 59.7°
Thus, ∠R = 180° - ∠P - ∠Q
= 180° - 42.8°- 59.7°
= 77.5°
PQ is the the distance of the ship moving. We can use the sinus equation
= 
= 
PQ = (
)(sin 59.7°)
= 9.29
2,150 estimated would be 2,000. Since she flies there and back multiply 2,000 by 2. Since she flies it twice multiply 4,000 by 2. Estimated: 8,000 miles. To find the exact miles Do the same thing but with 2,150: 2,150 times 2 = 4,300. 4,300 times 2 = 8,600. She flies exactly 8,600 miles per year :)
(f * g)(x) = 4x^2(x + 1)
4x^3 + 4x^2
Answer:
13
Step-by-step explanation:
First find the average the numbers (40 / 4 = 10)
2 are more and 2 are less
7, 9, 11, 13
The unsimplified fraction is 8/12 which can be reduced to 2/3
