CD = x
BC = y
AB = 85
BD = BC+CD = y+x
tan(angle) = opposite/adjacent
tan(28) = BC/AB
tan(28) = y/85
85*tan(28) = y
y = 85*tan(28)
y = 45.1953016912257
tan(angle) = opposite/adjacent
tan(31) = BD/AB
tan(31) = (y+x)/85
tan(31) = (45.1953016912257+x)/85
85*tan(31) = 45.1953016912257+x
51.0731526173427 = 45.1953016912257+x
51.0731526173427-45.1953016912257 = 45.1953016912257+x-45.1953016912257
5.877850926117 = x
x = 5.877850926117
So CD is roughly 5.877850926117 meters
Answer:
The length is 600 ft
Step-by-step explanation:
We can use the Pythagorean theorem since we know the diagonal which is the hypotenuse and the width
a^2 + b^2 = c^2
450 ^2 + b^2 = 750^2
b^2 = 750^2 - 450^2
b^2 =562500-202500
b^2 =360000
Taking the square root of each side
sqrt(b^2) = sqrt(360000)
b =600
<span>Raul only hit 19 times out of 45 bats.
Now, let’s find the average decimal value of Raul’s hit.
=> 19 hits
=> 45 bats
x = value in decimals
=> 19 = x * 45
=> 19 = 45x
Now, divide both sides with 45
=> 19/45 = 45x / 45
=> 0.4222222 = x
x = 0.422222……..
Since it is a repeating decimals, and we only need to find the thousandths
value. Let’s get the value of Thousandths.
=> 4 = tenths
=> 2 = hundredths
=> 2 thousandths
Therefore the value of 19 hits out of 45 bats in decimals is
=> .422 </span>
Answer: The first 6 terms are = 8, 10, 12,14,16,18
Step-by-step explanation:
The NTH term of an Arithmetic Sequence is given as
an = a1 + (n - 1 ) d
where a1 = First term given as 8 and
d= common difference given as 2
Therefore We have that
the first term
an = a1 + (n - 1 ) d = 8+(1-1) 2
a1= 8
second term=
an = a1 + (n - 1 ) d= a2= 8 + (2-1) 2
= 8+ 2(1) = 10
3rd term
an = a1 + (n - 1 ) d= a3= 8 + (3-1) 2
= 8+ 2(2)= 8 + 4=12
4th term
an = a1 + (n - 1 ) d= a4= 8 + (4-1) 2
= 8+ 2(3)= 8+6=14
5th term
an = a1 + (n - 1 ) d= a5= 8 + (5-1) 2
= 8+ 2(4)=8+ 8=16
6th term
an = a1 + (n - 1 ) d= a6= 8 + (6-1) 2
= 8+ 2(5)=8 +10 =18
