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aev [14]
3 years ago
6

A spinner is divided into 5 equal sections numbered 1 to 5. The theoretical probability of the spinner stopping on 3 is 20%. Whi

ch of the following is most likely the number of 3's spun in 10,000 spins?
A. 3358
B. 1243
C. 2589
D. 2067
Mathematics
1 answer:
adoni [48]3 years ago
8 0
1243 i believe my dood
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An American car company has designed a new high fuel efficiency vehicle that is rated at 55 miles per gallon. The company plans
Tju [1.3M]
The fuel usage would be approx. 23 km. per liter. The exact number would be 23.3829 km. per liter.
8 0
3 years ago
A medical student is conducting a study to track boys’ weight from age 5 to age 18. The student graphs some data and determines
katrin2010 [14]

Answer:

A. The increase in the number of pounds a boy gains each year.

Step-by-step explanation:

A medical student is conducting a study to track boys’ weight from age 5 to age 18. The student graphs some data and determines the line of best fit is  

y = 1.73x + 80.13 ............ (1)

where x represents the age of the boys and y represents the weight of the boy corresponding to his age.

Therefore, the slope of the equation (1) represents the increase in the number of pounds a boy gains each year. (Answer)

4 0
3 years ago
ASK YOUR TEACHER An article reported that for a sample of 42 kitchens with gas cooking appliances monitored during a one-week pe
xxMikexx [17]

Answer:

654.16-2.02\frac{165.23}{\sqrt{42}}=602.66    

654.16+2.02\frac{165.23}{\sqrt{42}}=705.66    

So on this case the 95% confidence interval would be given by (602.66;705.66)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=654.16 represent the sample mean

\mu population mean (variable of interest)

s=165.23 represent the sample standard deviation

n=42 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=42-1=41

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,41)".And we see that t_{\alpha/2}=2.02

Now we have everything in order to replace into formula (1):

654.16-2.02\frac{165.23}{\sqrt{42}}=602.66    

654.16+2.02\frac{165.23}{\sqrt{42}}=705.66    

So on this case the 95% confidence interval would be given by (602.66;705.66)    

7 0
4 years ago
At 106°F, a certain insect chirps at a rate of 67 times per minute, and at 108°F, they chirp 83 times per minute. Write an equat
Step2247 [10]

Answer:

y=8x-781

Here, x represents temperature and y denotes rate of chirping per minute.

Step-by-step explanation:

Let x represents temperature and y denotes rate of chirping per minute.

At 106°F, a certain insect chirps at a rate of 67 times per minute.

Take (x_1,y_1)=(106,67)

At 108°F, they chirp 83 times per minute.

Take (x_2,y_2)=(108,83)

Slope intercept form:

y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)

y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{16}{2})(x-106)\\\\y-67=8(x-106)\\y-67=8x-848\\y=8x+67-848\\y=8x-781

3 0
3 years ago
Which of the following is an arithmetic sequence with a common difference of +3?
Reil [10]
C.

4 + 3 7 + 3 1 0 + 3 1 3
8 0
3 years ago
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